The equilibrium `Cr_(2)O_(7)^(2-)hArr 2CrO_(4)^(2-)`

The equilibrium Cr_(2)O_(7)""^(2-)hArr2CrO_(4)""^(2-) is shifted to right in-

Following ions are equilibrium at Cr_(2) O_(7)^(2-) hArr CrO_(4)^(2-)

The equilibrium Cr_2O_7^(2-) hArr 2CrO_4^(2-)

The [CrO_(4)^(2-)] ions are equilibrium for the reaction, Cr_(2)O_(7)^(2-)+H_(2)Oharr2CrO_(4)^(2-)+2H^(+), "at" pH=4 is: