The binding energies of two nuclei `P^n` and `Q^(2n)` and x and y joules. If `2x gt y` then the energy released in the reaction `P^n + P^n to Q^(2n)`, will be

The co-efficients of the expansion of (1+x)^(2n-1) and (1+x)^(2n) are P and Q resp.Calculate the relation between P and Q.

If two sets P and Q ,n(P)=5 ,n(Q)=4 then n(P xx Q)=

If p and q are the coefficients of x^n in (1+x)^(2n-1) and (1+x)^(2n) respectively then 2p=

The coordinates of two points Pa n dQ are (x_1,y_1)a n d(x_2,y_2)a n dO is the origin. If the circles are described on O Pa n dO Q as diameters, then the length of their common chord is (a) (|x_1y_2+x_2y_1|)/(P Q) (b) (|x_1y_2-x_2y_1|)/(P Q) (|x_1x_2+y_1y_2|)/(P Q) (d) (|x_1x_2-y_1y_2|)/(P Q)

The coordinates of two points Pa n dQ are (x_1,y_1)a n d(x_2,y_2)a n dO is the origin. If the circles are described on O Pa n dO Q as diameters, then the length of their common chord is (|x_1y_2+x_2y_1|)/(P Q) (b) (|x_1y_2-x_2y_1|)/(P Q) (|x_1x_2+y_1y_2|)/(P Q) (d) (|x_1x_2-y_1y_2|)/(P Q)

The coordinates of two points Pa n dQ are (x_1,y_1)a n d(x_2,y_2)a n dO is the origin. If the circles are described on O Pa n dO Q as diameters, then the length of their common chord is (a) (|x_1y_2+x_2y_1|)/(P Q) (b) (|x_1y_2-x_2y_1|)/(P Q) (|x_1x_2+y_1y_2|)/(P Q) (d) (|x_1x_2-y_1y_2|)/(P Q)

The coordinates of two points Pa n dQ are (x_1,y_1)a n d(x_2,y_2)a n dO is the origin. If the circles are described on O Pa n dO Q as diameters, then the length of their common chord is (|x_1y_2+x_2y_1|)/(P Q) (b) (|x_1y_2-x_2y_1|)/(P Q) (|x_1x_2+y_1y_2|)/(P Q) (d) (|x_1x_2-y_1y_2|)/(P Q)

If 2 log_(8) N = p , log_(2) 2 N = q , and q - p = 4 , then the value of N is