In the electrochemical reaction,
`2Fe^(3+)+Zn rarr Zn^(2+) + 2Fe^(2+)`,
increasing the concentration of `Fe^(2+)` :

E^(o) for the reaction Fe + Zn^(2+) rarr Zn + Fe^(2+) is – 0.35 V. The given cell reaction is :

E^(o) for the reaction Fe + Zn^(2+) rarr Zn + Fe^(2+) is – 0.35 V. The given cell reaction is :

E^(0) for the reaction Fe + Zn^(2+) to Zn + Fe^(2+) is -0.35 V . The given cell reaction is

The E_(cell)^(0) for the reaction Fe+Zn^(2+)hArrZn+Fe^(3+) is -0.32 volt at 25^(@)C . What will be the equilibrium concentration of Fe^(2+) , when a piece of iron is placed in a 1MZn^(2+) solution?

The E_(cell)^(0) for the reaction Fe+Zn^(2+)hArrZn+Fe^(3+) is -0.32 volt at 25^(@)C . What will be the equilibrium concentration of Fe^(2+) , when a piece of iron is placed in a 1MZn^(2+) solution?

In the reaction : Zn + FeSO_4 rarr Zn SO_4 + Fe