Consider the situation as shown in the figure. If `mu_(1)` is the friction coefficient between block `A` and incline and `mu_(2)` is the friction coefficient between block `B` and incline. Find the acceleration of block `A` if (a) `mu_(1) = (1)/(5) , mu_(2) =(2)/(5)` and (b) `mu_(1) = (2)/(5) , mu_(2) = (1)/(5)`.

Consider the situation as shown in the figgure. The coefficent of friction between the blocks is mu . Find the acceleration of each block.

If coefficient of friction between both the block is mu- (1)/(2) . Find friction force acting between both block.

Figure shows two blocks in contact placed on an incline of angle theta = 30^(@) . The coefficient of friction between the block of mass 4 kg and the incline is m1, and that between 2 kg block and incline is mu_(2) . Find the acceleration of the blocks and the contact force between them if – (a) mu_(1) = 0.5 , mu_(2) = 0.8 (b) mu_(1) = 0.8 , mu_(2) = 0.5 (c) mu_(1) = 0.6 , mu_(2) = 0.1 " " [ Take g = 10m//s^(2) ]

In the arrangement shown in figure coefficient of friction between 5kg block and incline plane is mu=0.5 . Friction force acting on the 5kg block is

In the arrangement shown in figure coefficient of friction between 5kg block and incline plane is mu=0.5 . Friction force acting on the 5kg block is

A block is stationary on an inclined plane If the coefficient of friction between the block and the plane is mu then .

In the figure shown, if friction coefficient of block 1 kg and 2kg with inclined plane is mu_(1) = 0.5 and mu_(2) = 0.4 respectively, then

In the figure shown if friction coefficient of block 1kg and 2kg with inclined plane is mu_(1)=0.5 and mu_(2)=0.4 respectively, then

In the figure shown, if friction coefficient of block 1 kg and 2kg with inclined plane is mu_(1) = 0.5 and mu_(2) = 0.4 respectively, then