[3x-7y+10=0],[y-2x-3=0]

Solve the following system of equations: 3x-7y+10=0,quad y-2x-3=0

Solve [2x+3y-7=0],[3x+2y-8=0]

Solve the system: x + y - 2z = 0, 2x - 3y + z = 0, 3x - 7y + 10z = 0, 6x - 9y + 10z = 0.

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

Given the four lines with equations x+2y-3=0, 3x+4y-7=0, 2x+3y-4=0 and 4x+5y-6=0 , then:

Find x,y if [[3,2],[7,x]][[5,-2],[-7,y]]=[[1,0],[0,1]] .

Find the equations of the straight lines passing through the point (-3, 2) and making an angle of 45^(@ with the straight line 3x-y+4=0 (A) x-2y+7=0,2x+y+4= (B) x+2y+7=0,2x-y+4=0(c) x-2y-7=0,2x+y+4=0 (D) x-2y-7=0,2x+y-4=0