A particle is moving in a uniform magnetic field, then

A charged particle is moving in a uniform magnetic field. Then ______ .

What should be the angle between the velocity vector of the charged particle and the magnetic field to experience a maximum force, when a charged particle is moving in a uniform magnetic field?

A charged particle is moving in a uniform magnetic field and losses 4% of its KE. The radius of curvature of its path change by

A charged particle is moving in a uniform magnetic field in a circular path. Radius of circular path is R . When energy of particle is doubled, then new radius will be

A charge particle is moving in a uniform magnetic field ib a circular path. The energy of the particle is doubled . If the initial radius of he circular path was R , the radius of the new circular path after the energy is doubled will be

A charge particle is moving in a uniform magnetic field ib a circular path. The energy of the particle is doubled . If the initial radius of he circular path was R , the radius of the new circular path after the energy is doubled will be

(A) : The energy of charged particle moving in a uniform magnetic field does not change. (R) : Work done by magnetic field on the charge is zero.

The energy of a charged particle moving in a uniform magnetic field does not change. Why? Explain.

How does the radius of a circular path of a charged particle moving in a uniform magnetic field depend on its momentum and charge?

What is the path of a charged particle moving in a uniform magnetic field with initial velocity (i) parallel to the field? (ii) perpendicular to the field? (iii) at some angle with the direction of magnetic field.