" The perpendicular distance of "P(1,2,3)" from the line "

The perpendicular distance of the point (1,2,3) from the line (x-1)/(2)=(y-3)/(1)=(z-4)/(1)

A : The perpendicular distance from (1,4 -2) to the line joining (2,1,-2) (0,-5,1) is 3 sqrt(26)//7 R : The perpendicular distance from a point P to the line joining the point A,B is (|vec(AP) xx vec(AB)|)/(|vec(AB)|)

The perpendicular distance of the point (1,2,3) from the x-axis is -

The perpendicular distance from (1,2) to the line 5x+12y-3=0 is:

Perpendicular distance of the point (1, 2, 3) from the line (x-6)/3=(y-7)/2 = (z-7)/(-2) is

Perpendicular distance of the point (1, 2, 3) from the line (x-6)/3=(y-7)/2 = (z-7)/(-2) is

A plane P = 0 is the perependicular bisector of the line joining the points (2, 3, 4) and (6, 7, 8). The perpendicular distance of P = 0 from the origin is

A plane P = 0 is the perependicular bisector of the line joining the points (2, 3, 4) and (6, 7, 8). The perpendicular distance of P = 0 from the origin is

2/ Find the perpendicular distance of the point (1,0,0) from the line (x-1)/(2)=(y+1)/(-3)=(z+10)/(8) Also,and the coordinates of the foot of the perpendicular and the equation of the perpendicular.

Find the equation of the plane passing through the point A (1,2,1) and perpendicular to the line joining the points P(1,4,2) and Q(2,3,5) . Also, Find also the perpendicular distance of the plane from te line : (x + 3)/(2) = (y - 5)/(-1) = (z - 7)/(-1) .