[2x+y=5xz=0],[2x+2y=8]

The point of intersection of the diagonals of the rhombus formed by the lines 2x+y-5=0, x+2y+8=0, 2x+y+5=0, and x+2y-2=0 is

The line 3x + 2y = 6 will divide the quadrilateral formed y the lines x + y = 5, y – 2x = 8, 3y + 2x = 0 & 4y – x = 0 in

(a) 2x+y=5 ; 3x+2y=8

The line 3x+2y=6 will divide the quadrilateral formed by the lines x+y=5,y-2x=8,3y+2x=084y-x=0

The quadrilateral formed by the lines 2x-5y+7=0,5x+2y-1=0,2x-5y+2=0,5x+2y+3=0 is

The figure formed by the lines 2x+5y+4=0,5x+2y+7=0,2x+5y+3=0 and 5x+2y+6=0 is

If [[x + y, x-y],[2x - z, 0]] = [[5,3],[8,0]] find the value of x, y, z.

find x and y : 2x+y-5=0 3x+2y-8=0

det[[2x,xy-xz,y2x+z+1,xy-xz+yz-z^(2),1+y3x+1,2xy-2xz,1+y]]

2x - 5y + 4= 0 , 2x + y - 8 = 0