A tuning fork vibrates at 264 Hz. Find the length of the shortest closed organ pipe that will resonarte wilth the tuning fork. Speed of sound in air is `350ms^-1.

A tuning fork vibrates at 264 Hz . Find the length of the shortest closed organ pipe that will resonate with the tuning fork. Speed of sound in air is 350ms^-1 .

A tuning fork vibrates at 264 Hz . Find the length of the shortest closed organ pipe that will resonate with the tuning fork. Speed of sound in air is 350ms^-1 .

A tuning fork is vibrating at 250 Hz. The length of the shortest closed organ pipe that will resonate with the tuning fork will be (Take speed of sound in air as 340 ms^( -1) )

What should be the length of smallest closed organ pipe which will resonate with tuning fork of frequency 250Hz?

A stationary tuning fork is in resonance with an air column in a pipe . If the tuning fork is moved with a speed of 2ms^(-1) in front of the open end of the pipe and parallel to it , the length of the pipe should be changed for the resonance to occur with the moving tuning fork if the speed of sound in air is 320ms^(-1) , the smallest value of the percentage change required in the length of the pipe is _________.

A tuning fork of frequency n resonates with a closed organ pipe when the length of the shortest air columns are a and b respectively, then the speed of sound in air will be

What is minimum length of a tube, open at both ends, that resonates with tuning fork of frequency 350 Hz ? [velocity of sound in air = 350 m/s ]

What is minimum length of a tube, open at both ends, that resonates with tuning fork of frequency 350 Hz ? [velocity of sound in air = 350 m/s ]

Velocity of sound in air is 332 m//sec . The shortest length of an open pipe which will resonate with a tuning fork of frequency 166Hz is