`N_(2) + 3H_(2)hArr2NH_(3)` If temperature of following equilibrium reaction increases, then the reaction

The equilibrium constant for the reaction N_(2)+3H_(2)hArr2NH_(3) is 70 at a certain temperature. Hence, equilibrium constant for the reaction NH_(3)hArr(1)/(2)N_(2)+(3)/(2)H_(2) of the same temperature will be approximately

The equilibrium constant for the reaction N_(2)+3H_(2)hArr2NH_(3) "is" 70 at a certain temperature. Hence, equilibrium constant for the reaction NH_(3)hArr(1)/(2)N_(2)+(3)/(2)H_(2) of the same temperature will be approximately

A reaction N_(2)+ 3H_(2) hArr 2NH_(3) + 92 k.j is at equilibrium. If the concentration of N_(2) is increased the temperature of the system

A reaction N_(2)+ 3H_(2) hArr 2NH_(3) + 92 k.j is at equilibrium. If the concentration of N_(2) is increased the temperature of the system

If N_(2) + 3 H_(2) hArr 2NH_(3) ... (1) & N_(2) + 3H_(2) overset(Fe)(hArr) 2NH_(3).... (II) are in equilibrium at same temperature. Then

The equilibrium constant for the reaction N_(2) + 3H_(2) hArr 2NH_(3) is 'K' . Then the equilibrium constant for the reaction 2N_(2) + 6H_(2) hArr 4NH_(3) will be