`(n-1)P_r+r.(n-1)P_(n-1)` is equal to

Show that ""^(n)P_r =""^(n-1) P_r + r, ^(n-1) P_(r-1) Where the symbols have their usual meanings.

Prove that : ^nP_r= "^(n-1)P_r+r ^(n-1)P_(r-1) , for all natural numbers n and r for which the symbols are defined.

Prove that ^nP_r= ^(n-1)P_r+r^(n-1)P_(r-1) (notation used are in their usual meaning).

Prove that .^(n-1)P_r+r.^(n-1)P_(r-1)=^nP_r .

Prove that .^(n)P_(r)=.^(n-1)P_(r)+r.^(n-1)P_(r-1) .

What is ""^(n-1)P_(r )+ ""^(n-1)P_(r-1) ?

Prove that .^(n-1) P_r+r .^(n-1) P_(r-1) = .^nP_r

Prove that ^(n-1) P_r+r .^(n-1) P_(r-1) = .^nP_r

Prove that , ""^nP_r = ""^((n-1))Pr + r. ""^(n-1)P_((r-1))