IF `P` is any point within a `DeltaABC`, then `PA + CP` is

If P is a point on the plane of DeltaABC such that bar(PA) + bar(PB) + bar(PC) = 0 , then, for Delta ABC, the point P is

D is any point on the side BC of DeltaABC . P and Q are centroids of DeltaABD and DeltaADC respectively. Prove that PQ||BC .

A(-9,0),B(-1,0) are two points.If P is a point such that PA:PB=3:1, then the locus of P is

In the adjoining figure, P is an interior point of DeltaABC . Then prove that : AB+BC+CA lt 2(PA + PB +PC)

In DeltaABC , P is a point on the median AD . Extended BP and CP intersect AC and AB at Q and R respectively. Prove that RQ||BC .

ABC is an equilateral triangle where AB = a and P is any point in its plane such that PA = PB + PC. Then (PA^(2)+PB^(2)+PC^(2))/(a^(2)) is

ABC is an equilateral triangle where AB = a and P is any point in its plane such that PA = PB + PC. Then (PA^(2)+PB^(2)+PC^(2))/(a^(2)) is