According to equation, `C_(6)H_(6)(l)+15//2 O_(2)(g)rarr 6CO_(2)(g)+3H_(2)O(l), Delta H= -3264.4 "KJ mol"^(-1)` the energy evolved when 7.8 g benzene is burnt in air will be -

According to the equation C_(6)H_(6(l))+7/2 O_(2(g)) rarr 6CO_(2(g))+3H_(2)O_((l)), DeltaH=-xkJ The energy evolved when 3.9 gm of benzene is burnt in air is - 163.2 kJ heat of combustion of benzene is

According to the reaction C_(6)H_(6)+15//2O_(2)to3H_(2)O+6CO_(2) ( DeltaH=-3264.6 kJ // mol ) the energy evolved when 3.9g of benzene is burnt in air will be

According to the equation, C_6H_6(l)+15/2O_2(g)rarr3H_2O(l)+6C_2(g) triangleH =-3264.4kJ/mol, the energy evolved when 7.8 g of benzene is burnt in air will be:

The heat evolved in the combustion of benzene is given by the equation: C_(6)H_(6)(g) + (15)/(2) O_(2)(g) to 6CO_(2)(g) + 3H_(2)O(l), DeltaH = - 3264.6 kJ "mol"^(-1) The heat energy changes when 39 g of C_(6)H_(6) are burnt im an open ontainer will be:

The heat evolved in the combustion of benzene is given by. the equation: 'C_6 H_6(g)+(15)/2 O_2(g) rarr 6 CO_2^(g)+3 H_2 O(l), Delta H=-3264.6 kJ mol^(-1)' The heat energy change when '39 g' of 'C_6 H_6' are burnt in an open container will be:

The heat evolved in the combustion of benzene is given by the equation C_(6)H_(6)(l)+7(1)/(2)O_(2)(g)to 6CO_(2)(g)+3H_(2)O(l) , Delta H =- 781 Kcal mol^(-1) Which of the following quantities of heat will be evolved when 39 g of benzene is burnt in an open container

The heat evolved in the combustion of benzene is given by the equation C_(6)H_(6)(l)+7(1)/(2)O_(2)(g)to 6CO_(2)(g)+3H_(2)O(l) , Delta H =- 781 Kcal mol^(-1) Which of the following quantities of heat will be evolved when 39 g of benzene is burnt in an open container

The heat evolved in combustion of benzene is given by the following equation C_(6)H_(6)+15//2O_(2)to3H_(2)O+6CO_(2) : DeltaH=-3264.6 kJ Which of the following quantities of heat will be evolved when 39g of benzene are burnt in an open container ?