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If tantheta=(xsinphi)/(1-xcosphi) and ta...

If `tantheta=(xsinphi)/(1-xcosphi) and tanphi=(ysintheta)/(1-ycostheta),` then `x/y=` (A) `sinphi/sintheta` (B) `sintheta/sinphi` (C) `sinphi/(1-costheta)` (D) `sintheta/(1-cosphi)`

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