At some instant the velocity components of an electron moving between two charged parallel plates are `v_x=1.5xx10^5m//s` and `v_y=3.0xx10^6 m//s`.Suppose that the electric field between the plates is given by `E = (120 N//C) hatj`
. (a) What is the acceleration of the electron?
(b) What will be the velocity of the electron after its x-coordinate has changed by 2.0 cm?

First orbit velocity of electron is 2.1 xx 10^(6) m//s then the velocity of 3rd orbit electron is

An electron is accelerated in between two plates maintained at 1000 V . What is the energy in eV acquired by the electrons? (e=1.6 xx10^(-19) C)

The potential difference between two parallel plates is 10^(4) V. If the plates are separated by 0.5 cm, the force on an electron between the plates is

An electron beam is moving between two parallel plates having eletric field 1.125 xx 10^(-6) N//m . A magnetic field 3 xx 10^(-10) T is also applied so that beam of electrons do not deflect. The velocity of the electron is

Two parallel plates have equal and opposite charge. When the space between them is evacuated, the electric field between the plates is 2xx 10^(5) V/m. When the space is filled with dielectric, the electric field becemes 1xx10^(5) V/m. The dielectric constant of the dielectric material is

An electron is projected with an initial velocity of 10^(7)ms^(-1) into an electric field between two parallel plates 1 cm apart. The electron enters the field at a point midway between the plates. If the electron just misses the positivity charged plate as it emerges from the field, find the magnnitude of the electric density between the plates. (Length of each plate is 2 cm, mass of electron= 9xx10^(-31) kg and charge of electron =1.6xx10^(-19) C)