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[(sin18^(@))/(cos72^(@))],[" met for "]...

[(sin18^(@))/(cos72^(@))],[" met for "]

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Evaluate: (i) (sin 18^(@))/(cos 72^(@))

Evaluate: (sin18^(@))/(cos72^(@))

(sin 18^@)/( cos 72 ^@) = ?

sin18^(@)-cos72^(@) is equal of :

What is the value of (sin18^@)/(cos72^@) .

Evaluate : (sin 18^(@))/(cos72^(@))

Evalute: (b) (sin18^(@))/(cos72^(@))

Prove that (sin18^(@))/(cos72^(@))=1

(1) (sin18 ^ (@)) / (cos72 ^ (@)) (ii) (tan26 ^ (@)) / (cot64 ^ (@))