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I=int(0)^( pi)(x)/(1+sin x cos alpha)dx...

I=int_(0)^( pi)(x)/(1+sin x cos alpha)dx

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int_ (0) ^ (pi) (xdx) / (1 + cos alpha * sin x) = (pi alpha) / (sin alpha), 0

If int_(0)^((pi)/(2))(dx)/(1+sin x+cos x)=In2, then the value of int_(0)^((pi)/(2))(sin x)/(1+sin x+cos x)dx is equal to: