[" The rate of flow ( "V" ) of a liquid flowing through a "],[" pipe of radius "r" and a pressure gradient (P/l) is "],[" riven by Poiseuille's equation: "V=(pi)/(8)(Pr^(4))/(eta l)]

The rate of flow (V) of a liquid flowing through a pipe of radius r and pressure gradient (P//I) is given by Poiseuille's equation V = (pi)/(8)(Pr^4)/(etaI) Chack the dimensional correctness of this relation.

The rate flow (V) of a liquid through a pipe of radius (r ) under a pressure gradient (P//I) is given by V = (pi)/(8)(P R^4)/(I eta), Where eta is coefficient of visocity of the liquied. Check whether the formula is correct or not.

Using the method of dimensions, derive an expression for rate of flow (v) of a liquied through a pipe of radius (r ) under a pressure gradient (P//I) Given that V also depends on coefficient of viscosity (eta) of the liquied.

The rate of a flow V a of liquid through a capillary under a constant pressure depends upon (i) the pressure gradient (P/l) (ii) coefficient of viscosity of the liquid eta (iii) the radius of the capillary tube r. Show dimesionally that the rate of volume of liquid flowing per sec V∝ Pr^4 /ηl

The rate of flow Q (volume of liquid flowing per unit time) through a pipe depends on radius r , length L of pipe, pressure difference p across the ends of pipe and coefficient of viscosity of liquid eta as Q prop r^(a) p^(b) eta^(c ) L^(d) , then

Derive Poiseuille's formula for the volume of a liquid flowing per second through a pipe under streamlined flow.