If the function `f: Rsetminus` `{0}vec` given by `f(x)=1/x-2/(e^(2x)-1)` is continuous at `x=0,` then find the value of `f(0)`

If the function f:R backslash{0}rarr given by f(x)=(1)/(x)-(2)/(e^(2x)-1) is continuous at x=0 then find the value of f(0)

If the function f: R- {0}-> R given by f(x)=1/x-2/(e^(2x)-1) is continuous at x=0, then find the value of f(0)

If the function f: R- {0}-> R given by f(x)=1/x-2/(e^(2x)-1) is continuous at x=0, then find the value of f(0)

The function f:""R""~""{0}vec given by f(x)=1/x-2/(e^(2x)-1) can be made continuous at x = 0 by defining f(0) as

The function f : R - {0} to R given by f(x) = 1/x - 2/(e^(2x)-1) can be made continuous at x = 0 by defining f(0) as

The function f:R-{0}rarr R given by f(x)=(1)/(x)-(2)/(e^(2)x-1) can be made continuous at x=0 by defining f(0) as

if f(x)=(e^(x^(2))-cosx)/(x^(2)) , for xne0 is continuous at x=0 , then value of f(0) is

If the function f defined as f(x)=(1)/(x)-(k-1)/(e^(2x)-1),x!=0, is continuous at x=0, then the ordered pair (k,f(0)) is equal to: