The value of `DeltaH^(@)` for the reaction `Cu^(+)(g)+I^(-)(g)toCuI(g)` is -446kJ `mol^(-1)`. If the ionisation energy of `Cu(g)` is 745 kJ `mol^(-1)` and the electron affinity of I(g) is -295 kJ `mol^(-1)`, then the value of `DeltaH^(@)` for the formation of one mole of CuI(g) from Cu(g) and I(g) is:

The electron gain enthalpy Delta e_(g)H is -349 kJ mol^(-1) . If the ground state energy of Cl(g) is x kJ mol^(-1) . The ground state energy (in kJ mol^(-1) ) of Cl^(-) (g) is

The formation of O^(2-)(g) startng from O(g) is endothermic by 603 kJ mol^(-1) . If electron gain enthalpy of O(g) is -141 kJ mol^(-1) , the second electron gain enthalpy of oxygen would be :

The value of DeltaH for the given reaction at 298K is -282.85 kJ*mol^(-1) . Calculate the change in intenral energy: CO(g)+(1)/(2)O_(2)(g) to CO_(2)(g) .

The DeltaH_(f)^(0)(KF,s) is -563 kJ mol^(-1) . The ionization enthalpy of K(g) is 419 kJ mol^(-1) . and the enthalpy of sublimation of potassium is 88 kJ mol^(-1) . The electron affinity of F(g) is 322 kJ mol^(-1) and F-F bond enthalpy is 158 kJ mol^(_1) . Calculate the lattice enthalpy of KF(s) . The given data are as follows: (i) K(s)+1//2F_(2)(g)rarrKF(s)" "DeltaH_(f)^(0)= -563 kJ mol^(-1) (ii) K(g)rarrK^(+)(g)+e^(-)" "Delta_("Ioniz")^(0)=419 kJ mol^(-1) (iii) K(s)rarrK(g)" "DeltaH_("sub")^(0)=88kJ mol^(-1) (iv) F(g)+e^(-)rarrF^(-)(g)" "DeltaH_(eg)^(0)= -322 kJ mol^(-1) (v) F_(2)(g)rarr2F(s)" "DeltaH_("diss")^(0)= 158 kJ mol^(-1) (vi) K^(+)(g)+F^(-)(g)rarrKF(s)" " DeltaH_(L)^(0)=?

The DeltaH_(f)^(0)(KF,s) is -563 kJ mol^(-1) . The ionization enthalpy of K(g) is 419 kJ mol^(-1) . and the enthalpy of sublimation of potassium is 88 kJ mol^(-1) . The electron affinity of F(g) is 322 kJ mol^(-1) and F-F bond enthalpy is 158 kJ mol^(_1) . Calculate the lattice enthalpy of KF(s) . The given data are as follows: (i) K(s)+1//2F_(2)(g)rarrKF(s)" "DeltaH_(f)^(0)= -563 kJ mol^(-1) (ii) K(g)rarrK^(+)(g)+e^(-)" "Delta_("Ioniz")^(0)=419 kJ mol^(-1) (iii) K(s)rarrK(g)" "DeltaH_("sub")^(0)=88kJ mol^(-1) (iv) F(g)+e^(-)rarrF^(-)(g)" "DeltaH_(eg)^(0)= -322 kJ mol^(-1) (v) F_(2)(g)rarr2F(s)" "DeltaH_("diss")^(0)= 158 kJ mol^(-1) (vi) K^(+)(g)+F^(-)(g)rarrKF(s)" " DeltaH_(L)^(0)=?

The heat of formation of NH_(3)(g) is -46 " kJ mol"^(-1) . The DeltaH (in " kJ mol"^(-1) ) of the reaction, 2NH_(3)(g)rarrN_(2)(g)+3H_(2)(g) is