A tuning fork vibrats with frequnecy `256 Hz` and gives one beat per seond with the third normal mode of vibration of an open pipe. What is the length of the pipe (Speed of sound in air is `340 ms^(-1)`)

Give equation of normal mode of vibration for closed pipe.

A cylindrical pipe of length 28 cm closed at one end is found to be at resonance when a tuning fork of frequency 850Hz is sounded near the open end. Find the mode of vibration of the air in the pipe value of the end - correction. (take the speed of sound in air as 340 m/s)

A closed organ pipe can vibrate at a minimum frequency of 500 Hz. Find the length of the tube. Speed of sound in air = 340 m s^-1 .

A closed organ pipe can vibrate at a minimum frequency of 500 Hz. Find the length of the tube. Speed of sound in air = 340 m s^-1 .

A closed organ pipe can vibrate at a minimum frequency of 500 Hz. Find the length of the tube. Speed of sound in air = 340 m s^-1 .

Derive an equation for the first mode of vibration of an air column in an open organ pipe.

Two closed organ pipes give 10 beats between the fundamental when sounded together. If the length of the shorter pipe is 1m then the length of the longer pipe will be (speed of sound in air is 340ms^(-1) )

The first overtone of an open pipe and the fundamental tone of a closed pipe give 5 beats pe second when sounded together. If the length of the closed pipe is 25 cm, what are the possible length of the open pipe ? (Velocity of sound in air is 340 ms^(-1) )

A tuning fork vibrates at 264 Hz . Find the length of the shortest closed organ pipe that will resonate with the tuning fork. Speed of sound in air is 350ms^-1 .