For the equilibrium `2SO_(2)(g)+O_(2)(g) 2SO_(3)(g),DeltaH=-198KJ`, the equilibrium concentration of `SO_(3)` will be affected by

The equilibrium constant for the reaction 2SO_(2)(g)+O_(2)(g)hArr 2SO_(3)(g) is 256 at 1000 K. The equilibrium constant for the reaction : SO_(3)(g)hArr SO_(2)(g)+1//2 O_(2)(g) is :

Consider the reaction cquilibrium, 2SO_(2(g)) + O_(2(g)) hArr 2 SO_(3(g)) , Delta H^(@) = - 198KJ . On the basis of Le Chatelier's principle, the condition favourable for the forward reaction is

Consider the reaction cquilibrium, 2SO_(2(g)) + O_(2(g)) hArr 2 SO_(3(g)) , Delta H^(@) = - 198KJ . On the basis of Le Chatelier's principle, the condition favourable for the forward reaction is

Consider the reaction : SO_(2)(g)+(1)/(2)O_(2)(g) rarr SO_(3)(g),DeltaH=-98.3kJ If the enthalpy of formationof SO_(3)(g) is -395.4kJ , then the enthalpy of formation of SO_92)(g) is

For the equilibrium 2SO_(3(g))hArrSO_(2(g))+O_(2(g)) , the value of equilibrium constant is 4.8xx10^(-3) at 700^(@)C . At equilibrium, if the concentration of SO_(3) and SO_(2) are 0.60M and 0.15M respectively. Calculate the concentration of O_(2) in the equillibrium mixture.

For the equilibrium 2SO_(3(g))hArrSO_(2(g))+O_(2(g)) , the value of equilibrium constant is 4.8xx10^(-3) at 700^(@)C . At equilibrium, if the concentration of SO_(3) and SO_(2) are 0.60M and 0.15M respectively. Calculate the concentration of O_(2) in the equillibrium mixture.