A car of mass m starts from rest and acquires a velocity along east `upsilon = upsilonhati (upsilon gt 0)` in two seconds Assuming the car moves with unifrom acceleration the force exerted on the car is .

A car of mass m starts from rest and acquires a velocity along east upsilon = upsilonhati (upsilon gt 0) in two seconds Assuming the car moves with uniform acceleration the force exerted on the car is .

A car of mass m starts from rest and acquires a velocity along east, v - vhat(i) (v gt 0) in two seconds. Assuming the car moves with uniform acceleration, the force exerted on the car is

A car of mass m starts from rest and acquires a velocity along east vec v = vhati (v>0) in two seconds. Assuming the car moves with uniform acceleration, the force exerted on the car is

A car of mass 1200 kg starts from rest and acquires a uniform velocity of 18 m/s. What is the kinetic energy of the car ?

A car starting from rest acquires a velocity 180 m s^(-1) in 0.05 h. Find the acceleration.

A car start from rest and acquire a velocity of 54 km/h in 2 sec. Find (i) the acceleration (ii) distance travelled by car assume motion of car is uniform?

A car starts from rest and moves with a uniform acceleration of 1 m//s^2 ? for 10 seconds. It then moves with a uniform velocity for 30 seconds. The brakes are then applied and the car is brought to rest in 10 seconds. Find the total distance covered by the car.

A car starts from rest and covers 25m in 5s. Calculäte the acceleration of the car.

A car starting from rest acquires a velocity of 54 "kmh"^(-1) min 20 s. Calculate the acceleration of the car in S.I. unit.

A car starts from rest and accelerates at a constant rate in a straight line. In the first second, the car covers a distance of 2.0 meters. How much additional distance will the car cover during the second second of its motion ?