Sum the series : `tan^(- 1)(4/(1+3.4))+tan^(- 1)(6/(1+8.9))+tan^(- 1)(8/(1+15.16))+............oo` is :

tan^(-1)((3)/(4))+tan^(-1)((3)/(5))-tan^(-1)((8)/(19))=

Find - tan^(-1)((3)/(4))+tan^(-1)((3)/(5))-tan^(-1)((8)/(19))=

tan^(- 1)(1/4)+tan^(- 1)(2/9)=1/2tan^(- 1)(4/3)

tan^(- 1)(1/4)+tan^(- 1)(2/9)=1/2tan^(- 1)(4/3)

"tan"^(-1)((1)/(3))+ "tan"^(-1)((2)/(9)) + tan^(-1)((4)/(3^(3))) + ....oo is equal to

Find the sum of the series : (tan^(-1))(1)/(3)+(tan^(-1))(2)/(9)+...+(tan^(-1))(2^(n-1))/(1+2^(2n-1))+......oo

Prove that: tan^(-1)(3/4)+tan^(-1)(3/5)-tan^(-1)(8/19)=pi/4

The sum of tan ^(-1) (1)/(2)+tan ^(-1) (1)/(8)+tan ^(-1) (1)/(18)+.. is

tan ^ (- 1) ((3) / (4)) + tan ^ (- 1) ((3) / (5)) + tan ^ (- 1) ((8) / (19))

Prove that : tan^(-1)(1/2)+tan^(-1)(1/5)+tan^(-1)(1/8)=pi/4