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Find the point in which the line (x+1)/-...

Find the point in which the line `(x+1)/-1=(y-12)/5=(z-7)/2` cuts the surface `11x^2 - 5y^2+z^2 = 0`.

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Find the point of intersection of the line (x-2)/3 = (y + 1)/4 = (z - 2)/12 and the plane x - y + z = 5.

Find the distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/2=(y+1)/4=(z-2)/12 and the plane x-y+z=5.

Statement 1: A point on the line (x+2)/3=(y+1)/2=(z-3)/2 at a distance 3sqrt(2) from the point (1,2,3) lies on the lne (x+7)/5=(y+t)/4=(z-2)/1 Statement 2: If d is the distance between the point (-1,-5,-10) and the point of intersectionof the line (x-2)/3=(y+1)/4=(z-2)/12 with the plane x-y+z=5 then d=13

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Find the distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) and the plane x-y+z=5