A `mu F` capacitor is charged by a `400 V` supply through `0.1 M Omega` resistance. The time taken by the capacitor to develop a potential difference of `300 V` is : (Given `log_(10) 4 = 0.602`)

A 8 mu F capacitor is charged by a 400 V supply through 0.1 M Omega resistance. The time taken by the capacitor to develop a potential difference of 300V is : (Given log_(10)4 = 0.602 )

A 10 mu F capacitor is charged by a 30 V dc supply and then connected across an uncharged 50 mu F capacitor. Calculate The final potential difference across the combination.

A 4muF capacitor is charged to 400 V. If its plates are joined through a resistance of 2kOmega , then heat produced in the resistance is

A 4muF capacitor is charged to 400 V. If its plates are joined through a resistance of 4kOmega , then heat produced in the resistance will be

A 4 muF capacitor is charged to 400 V. If its plates are joined through a resistance of 2Komega , then heat produced in the resistance is

A 4 mu F capacitor is charged to 400 V and then its plates are joined through a resistance of 1 K Omega . The heat produced in the resistance is

A capacitor of capacitance C=1 muF is suddenly connected to a battery of 100 volt through a resistance R =100Omega . The time taken for the capacitor to be charged to get 50 V is : [Take ln 2 = 0.69]