A photon and an electron have equal energy `E . lambda_("photon")//lambda_("electron")` is proportional to

The energy of a photon is equal to the kinetic energy of a proton. The energy of the photon is E. Let lambda_1 be the de-Broglie wavelength of the proton and lambda_2 be the wavelength of the photon. The ratio (lambda_1)/(lambda_2) is proportional to (a) E^0 (b) E^(1//2) (c ) E^(-1) (d) E^(-2)

The energy of a photon is equal to the kinetic energy of a proton. The energy of the photon is E. Let lambda_1 be the de-Broglie wavelength of the proton and lambda_2 be the wavelength of the photon. The ratio (lambda_1)/(lambda_2) is proportional to (a) E^0 (b) E^(1//2) (c ) E^(-1) (d) E^(-2)

A proton with KE equal to that a photono (E = 100 keV). lambda_(1) is the wavelength of proton and lambda_(2) is the wavelength of photon. Then lambda_(1)/lambda)_(2) is proportional to:

The energy of a photon is E which is equal to the kinetic energy of a proton.If lambda1 be the de-Broglie wavelength of the proton and lambda2 be the wavelength of the photon,then the ratio (lambda_(1))/(lambda_(2)) is proportional to

the energy of photon is equal to the kinetic energy of a porton,If lambda_1 is the De-Broglie wavelength of a proton, lambda_2 the wavelength associated with the proton and if the energt of the protonis E, then (lamda_1//lambda_2) is proportional to

An electron and a proton possess same kinetic energy. Then lambda_e//lambda_p =

A photon and an electron both have wavelength 1 Å . The ratio of energy of photon to that of electron is

A photon and an electron both have wavelength 1 Å . The ratio of energy of photon to that of electron is

A photon and an electron have the same wavelength then, the velocity of photon is