A parallel plate capacitor is first connected to a constant voltage source. It is then disconnected and ·then immersed in a liqnid dielectric, then:

A parallel-plate capacitor with vertical plates is connected to a voltage source and then submerged into a liquid dielectric. How does the level of the dielectric between the plates change in the process? Explain the change of the energy stored by the capacitor

When a parallel plate capacitor is connected to a source of constant potential difference

A parallel plate air-filled capacitor is charged by connecting it across a voltage source for a long time. It is then disconnected from the source and connected across a voltmeter. How the voltage reading in the voltmeter will be affected if a dielectric is inserted between the plates of the capacitor? State your assumptions if any in the explanation.

Two identical parallel plate capacitors are placed in series and connected to a constant voltage source of V_0 volt. If one of the capacitors is completely immersed in a liquid with dielectric constant K, the potential difference between the plates of the other capacitor will change to -

Two identical parallel plate capacitors of same dimensions joined in series are connected to a constant voltage source. When one of the plates of one capacitor are brought closer to the other plate :

STATEMENT-1: A parallel plate capacitor is charged by a battery of voltage V . The battery is then disconnected. If the space between the plates is filled with a dielectric, the enegry stroed in the capacitor will decrease STATEMENT-2: The capacitance of a capacitor increases due to the introduciton of a dielectric between the plates.