A 1 MeV proton is sent against a gold leaf `(Z=79)`. Calculate the distance of closest approach for head-on collision.

A n alpha -particle of velocity 1.6xx10^(7) m s^(-1) approaches a gold nucleii (Z=79) . Calculate the distance of closest approach. Mas of an alpha -particle =6.6xx10^(-27) kg .

An alpha -particle having kinetic energy of 7.5 MeV is scattered by gold (Z=79) mucleus through 180^(@) . Calculate the distance of closest approach.

A beam of beryllium nucleus (z = 4) of kinetic energy 5.3 MeV is headed towards the nucleus of gold atom (Z = 79). What is the distance of closest approach?

An alpha particle having KE equal to 8.7MeV is projected towards the nucleus of copper with Z=29. Calculate its distance of closest approach.

A beam of alpha -particle of velocity 2.1xx10^(7)m//s is scattered by a gold ofil (Z=79). Find the distance of closest approach of alpha - particle to the gold nucleus. for alpha -particle, 2e//m=4.8xx10^(7)kg^(-1) .

In a head on collision between an alpha particle and gold nucleus (Z=79), the distance of closest approach is 39.5 fermi. Calculate the energy of alpha -particle.

An alpha particle of 10 MeV is moving forward fo a head on collision. What will be the distance of closest approach from the nucleus o atomic number Z = 29 ?

An alpha - particle of 10 MeV is moving forward for a head on collision. What will be the distance of closest approach from the nucleus of atomic number Z = 50 ?

In the original experiment, Geiger and Marsden calculated the distance of closest approach to the gold nucleus (Z=79)- of a 7.7MeV alpha particle before it comes momentarily to rest and reverses its direction. What is its value?