The relative density of material of a body is found by weighting it first in air and then in water . If the weight in air is `( 5.00 +- 0.05) N` and the weight in water is `(4.00 +- 0.05) N`. Find the relative density along with the maximum permissible percentage error.

The relative density of a material of a body is found by weighing it first in air and then in water. If the weight of he body in air is W_(1) = 8.00 +- N and the weight in water is W_(2) = 6.00 +- 0.05 N , then the relative density rho_(r ) = W_(1)//( W_(1) - W_(2)) with the maximum permissible eror is

The relative density of a material of a body is found by weighing it first in air and then in water. If the weight of he body in air is W_(1) = 8.00 +- N and the weight in water is W_(2) = 6.00 +- 0.05 N , then the relative density rho_(r ) = W_(1)//( W_(1) - W_(2)) with the maximum permissible eror is

The relative density of a material is found by weighing the body first in air and then in water . If the weight in air is ( 10.0 +- 0.1) gf and the weight in water is ( 5.0 +- 0.1) gf , then the maximum permissible percentage error in relative density is

The relative density of a material is found by weighing the body first in air and then in water . If the weight in air is ( 10.0 +- 0.1) gf and the weight in water is ( 5.0 +- 0.1) gf , then the maximum permissible percentage error in relative density is

The relative density of a material is found by weighing the body first in air and then in water. If the weight in air is (10.0 pm.01)N and weight and water is (5.0 pm 0.1)N , what would be the maximum percentage error in relative density?

The relative density of a material is found by weighing the body first in air and then in water. If the weight in air is (20.0 pm0.1)N and weight and water is (10.0 pm 0.1)N , what would be the maximum percentage error in relative density?

The relative density of a material of a body is found by weighing it first in air and then in water. If the wt. of the body in air is W_(1)=8*00+-0*05 newton and weight in water is W_(2)=6*00+-0*05 newton. Then the relative density, p_(r)=(W_(1))/(W_(1)-W_(2)) with the maximum permissible error is :