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Calculate the percentage of SN^(-1) prod...

Calculate the percentage of `SN^(-1)` product, if `(R )-2`-Chloro butane on reaction with `NaOH//H_(2)O` and acetone gives `98%` inverted product.

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Optically pure (+)-2 -chlorooctane, [alpha] = +40^@ , reacts with aq. NaOH in acetone to give optically pure (-)-2 -octanol, [alpha] = -12.0^@ . With partically racemised chloro compound whose [alpha] = + 30^@ , the [alpha] of alcohal product is - 6.0^@ . Calculate : (a) The percentage optical purity of partially racemised chloro compound and alcohol. (b) The percentage of inversion and racemisation. (c) The percentage of front-side and back-side attacks. (d) What interference can be drawn from the data in part (a) of the above example, about the mode of 2^@ alky1 halide. ( e) Give the rate expression. In terms if the expression, decrease the experimental changes for encourage (i) SN^1 , (ii) SN^2 ,