Steel and copper wires of same length are stretched by the same weight one after the other. Young's modulus of steel and copper are `2xx10^(11)(N)/(m^2)` and `1.2xx10^(11)(N)/(m^2)`. The ratio of increase in length is

Equal increase in length occurred in two wires, one is of steel of cross sectional area 3.0 xx10^-5 m^2 and another one is of copper of cross sectional area 4.0xx10^-5m^2 , by applying equal load on them. If Young's modulus of steel and copper are 2.0xx10^11 Nm^-2 and 1.0xx10^11Nm^-2 respectively, then the ratio of their initial lengths will be

What is the work done per unit volume when a steel wire is stretched by 0.2% of its original length ? (Young's modulus of steel is 2xx10^(11)N//m^(2) )

A steel wire of length 600cm and diameter 1.2 mm is stretched through 4 mm by a load. Calculate the work done. Young's modulus of steel = 2xx 10^(11) Nm^(-2) .

A copper wire and a steel wire of radii in the ratio 1:2, lengths in the ratio 2:1 are stretched by the same force. If the Young's modulus of copper = 1.1 xx 10^11Nm^(-2) find the ratio of their extensions (young's modulus of steel = 2 xx 10^11 N//m^2) .

The Young's modulus of a wire of length 2m and area of cross section 1 mm^(2) is 2 xx 10^(11) N//m^(2) . The work done in increasing its length by 2mm is

A steel wire of length 4 m and diameter 5 mm is stretched by kg-wt. Find the increase in its length if the Young's modulus of steel wire is 2.4 xx 10^(12) dyn e cm^(-2)

Young 's modulus of steel is 2.0 xx 10^(11)N m//(2) . Express it is "dyne"/cm^(2) .