The `NH_(3)` evolved from `2.8` gm sample of protein was absorbed in 45 ml of `0.2 M` `HNO_(3)`. The excess acid required 20 ml of `0.05 M` `NaOH %` of N in the sample will be :

The NH_(3) evolved due to complete conversion of N from 1.12g sample of protein was absorbed in 45 "ml of" 0.4N HNO_(3) . The excess acid required 20 "ml of" 0.1N NaOH . The % N in the sampl is:

The NH_3 evolved due to complete conversion of N from 1.12g sample of protien was absorbed in 45mL of 0.4 NHNO_3 . The excess acid required 20mL of 0.1NNaOH . The % N in the sample is :

The NH_3 evolved due to complete conversion of N from 1.12g sample of protien was absorbed in 45mL of 0.4 NHO_3 . The excess acid required 20mL of 1.0NaOH . The % N in the sample is :

During the estimation of nitrogen in an organic compound by Kjeldhal's method, the ammonia evolved from 0.5g of the compound was absorbed in 50 ml of 0.5 M H_(2)SO_(4) . The residual acid required 60 ml of 0.5 M NaOH solution. The percentage of nitrogen in the compound is

During the estimation of nitrogen in an organic compound by Kjeldhal's method, the ammonia evolved from 0.5g of the compound was absorbed in 50 ml of 0.5 M H_(2)SO_(4) . The residual acid required 60 ml of 0.5 M NaOH solution. The number of grams of NH_(3) releaed in the process is

0.303 g fo sample was analysed for nitrogen by Kjeldahl's method. The ammonia gas evolved was absorbed in 50 ml of 0.05 M H_(2)SO_(4) . The excess acid required 25 ml of 0.1 M NaOH for neutralisation.

0.50 g of an organic compound was Kjeldahlised and the NH_(3) evolved was absorbed in50 ml of 0.5 M H_(2)SO_(4) . The residual acid required 60cm^(3) of 0.5 M NaOH . The percentage of nitrogen in the organic compound is

An organic compound contains 69.4% carbon and 5.8% hydrogen. A sample of 0.303 g of this compound was analysed for nitrogen by Kjeldahl's method. The ammonia evolved was absorbed in 50 mL of 0.05 M H_2 SO_4 . The excess acid required 25 mL of 0.1 M NaOH for neutralisation. Determine the molecular formula of the compound, if its molecular mass is 121.