Calculate the emf of the following concentration cell at `25^(@)C`:
`Ag(s)|AgNO_(3) (0.01 M)||AgNO_(3) (0.05 M)|Ag (s)`

Calculate the emf of the following cell at 25^(@)C Ag(s)|AgNO_(3) (0.01 M)||AgNO_(3) (0.05 M)|Ag (s)

Calculate the emf of the following cell at 25^(@)C Ag(s)|AgNO_(3) (0.01" mol "Kg^(-1))| AgNO_(3) ("0.05 mole "Kg^(-1))|Ag(s)

Calculate the emf of the following cell at 25^(@)C Ag(s) |Ag+ (10^(-3)M) | |Cu 2+ (10^(-1)M | Cu(s) :

Calculate the emf of the following cell at 25^(@)C : Ag+(0.001M|Ag(S)||Cu(s) |Cu^(2+)(10^(-1)M), E0Cell =0.46V

The EMF of the following cell is 0.86 volts Ag|AgNO_(3)(0.0093M)||AgNO_(3)(xM)|Ag . The value of x will be

The value of the reaction quotient, Q for the following cell is Zn(s)|Zn^(2+) (0.01 M)||Ag^(+) (1.25 M)|Ag(s)

Calculate the e.m.f. of the cell in which the following reaction takes place: Ni(s) + 2Ag^(+)(0.004 M) → Ni^(2+)(0.1 M) + 2Ag (s) Given that E^(@) Cell =1.05V