From a solid circular cylinder with height 10 cm and radius of the base 6 cm, a circular cone of the same height and same base is removed. Find the volume of remaining solid and also find the whole surface area.

Explanation

Given, r=6cm, h=10cm.

Volume of remaining solid= `pir^2h - 1/3pir^2h`=`2/3pir^2h`

=`2/3*22/7*6*6*10=5280/7cm^3`

Total Surface area=`2pirh+ pir^2+ pirsqrt(r^2+h^2)`
=`22/7(2*6*10+6*6+6*sqrt(6*6+6*10))`
=`22/7(156+ 12sqrt34)cm^2`