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" 29."sin^(8)A-cos^(6)A=(sin^(2)A-cos^(2...

" 29."sin^(8)A-cos^(6)A=(sin^(2)A-cos^(2)A)(1-2sin^(2)A cos^(2)A)

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Show that: sin^(8)A-cos^(8)A=(sin^(2)A-cos^(2)A)(1-2sin^(2)A cos^(2)A)

Show that: sin^(8)A-cos^(8)A=(sin^(2)A-cos^(2)A)(1-2sin^(2)A*cos^(2)A)

Show that (i) sin^(8)A-cos^(8)A=(sin^(2)A-cos^(2)A)(1-2sin^(2)A.cos^(2)A) (ii) (1)/(sec A-tan A)-(1)/(cos A)=(1)/(cos A)-(1)/(sec A + tan A)

Show that (i) sin^(8)A-cos^(8)A=(sin^(2)A-cos^(2)A)(1-2sin^(2)A.cos^(2)A) (ii) (1)/(sec A-tan A)-(1)/(cos A)=(1)/(cos A)-(1)/(sec A + tan A)

Show that (i) sin^(8)A-cos^(8)A=(sin^(2)A-cos^(2)A)(1-2sin^(2)A.cos^(2)A)

int(sin^(8)x-cos^(8)x)/(1-2sin^(2)x cos^(2)x)dx

sin^(6)A + cos^(6)A + 3sin^(2)A.cos^(2)A=

int(sin^(8)x-cos^(8)x)/(1-2sin^(2)x cos^(2)x)dx=

sin ^ (8) A-cos ^ (8) A = (sin ^ (2) A-cos ^ (2) A) (1-2sin ^ (2) A cos ^ (2) A)

int (sin^(8)x-cos^(8)x)/(1-2sin^(2)x cos^(2)x)dx =