In `DeltaABC, D` is the mid-pointpoint of BC and E is mid-point of `AD. BE` is produced to meet the side AC in F.Then BF is equal to

E is the mid-point of the median AD of a DeltaABC . If B is extended it meets the side AC at F, then CF is equal to

In triangleABC, AD is the median through A and E is the mid point of AD. BE is produced so as to meet AC in F. prove that AF=1/3AC

In ABC,AD is the median through A and E is the mid-point of AD.BE produced meets AC in F (Figure).Prove that AF=(1)/(3)AC .

In DeltaABC , D is the midpoint of side BC, E is mid point of AD, F is midpoint of BE and G is mid-point of FC. What part of the area of DeltaABC is the area of DeltaEFG ?

A(a+1, a-1), B(a^(2)+1, a^(2)-1) and C(a^(3)+1,a^(3)-1) are given points. D (11, 9) is the mid point of AB and E (41, 39) is the mid point of BC. If F is the mid point of AC then (BF)^(2) is equal to K^(2) , where K =

In A ABC, E is mid-point of the median AD and BE produced meets side AC at point Q. Show that BE : EQ = 3:1.

In figure, ABC is a triangle with angle B = 90^@, BC = 3cm and AB = 4cm. D is a point on AC such that AD = 1cm and E is the mid- point of AB. Join D and E and extend DE to meet CB extended at F. Then BF is equal to

In a triangle ABC, AD is a medium and E is mid-point of median AD. A line through B and E meets AC at point F.