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If A is the void set varphi then P(A) ha...

If `A` is the void set `varphi` then `P(A)` has just one element `varphi` i.e. `P(varphi)={varphi}` So number of elements of `P[P(P(varphi))] `is .

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`P(phi)={phi}`

` therefore P(P(phi))={phi,{phi}} `

`Rightarrow P[P(P(phi))]={phi,{phi},{{phi}},{phi,{phi}}}`

so `P[P(P(phi))]` consists of `4` elements

` n[P[P(P(phi))]]=4`
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