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Show that n{P{P(P(varphi))}}=4....

Show that `n{P{P(P(varphi))}}=4.`

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We know that `P(set) = 2^n` where set has n elements
So if set empty set,`n = 0`
`P{empty set} = 2^0=1`
`P{P{empty set}}=2^1= 2`
`P{P{P{empty set}}}=2^2=4`
Hence` n (P{P{P{empty set}}})=4`
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