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Total vapour pressure of mixture of 1 mo...

Total vapour pressure of mixture of 1 mole of volatile component A `(P_(A)^(@)=100 mm Hg)` and 3 mole of volatile component `B (P_(B)^(@)=80 mm Hg)` is `90 mm Hg`. For such case `:`

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Total vapour pressure of mixture of 1 mole of volaile components A ( P_(a^(%) )=100 mm Hg) and 3 mole of volatile component B( P_B^(@) =80 mm Hg ) is 90 mm Hg. For such case:

Total vapour pressure of mixture of 1 mole of volaile components A ( P_(a^(%) )=100 mm Hg) and 3 mole of volatile component B( P_B^(@) =80 mm Hg ) is 90 mm Hg. For such case:

Total vapour pressure of mixture of 1 mole of volaile components A ( P_(a^(%) )=100 mm Hg) and 3 mole of volatile component B( P_B^(@) =80 mm Hg ) is 90 mm Hg. For such case:

Total vapour pressure of mixture of 1 mol of volatile component A( p_(A)^(@)=100 mm Hg) and 3 mol of volatile component B( p_(B)^(@) =60 mm Hg) is 75 mm. For such case:

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Total vapour pressure of mixture of 1 mol of volatile component A(P_(A^(@))=100mmHg) and 3 mol of volatile component B(P_(B^(@)=80 mmHg) is 75mm . For such case:

Total vapour pressure of mixture of 1 mol of volatile component A(P_(A^(@))=100mmHg) and 3 mol of volatile component B(P_(B^(@)=60 mmHg) is 75mm . For such case:

Total vapour pressure of mixture of 1 mol volatile component A(P^(@)A="100 mm Hg") and 3 mol of volatile component B(P^(@)B="60 mm Hg") is 75 mm. For such case -

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The total vapour pressure of a mixture of 1 mole of A ( P_A = 200 mm Hg ) and 3 mole of B ( P_B= 360 mm Hg) is 350 mm Hg. Then