Find the inverse relation `R^(-1)` in the following case: `R ` is a relation from `{11 , 12 , 13}to\ {8, 10 , 12}` defined by `y=x-3.`

Explanation

Let A= {11,12,13},B= {8,10,12}

Then,`R={(x,y):epsilonin A,y in B,Y=X-3}`

When `x=11,y=8`

When `x=12,y=9` not in B

When `x=13,y=10`

Thus `R={(11,8),(13,10)}`
and `R^(-1)={(8,11),(10,13)}`