If `R={(x , y): x , y in Z , x^2+y^2lt=4}` is a relation on Z,`\ ` then domain of `R` is `{0,1,2}` b. `{0,-1,-2}` c. `{-2,-1,0,1,2}` d. none of these

Explanation

To find the domain of the relation \( R = \{(x, y) : x, y \in \mathbb{Z}, x^2 + y^2 \leq 4\} \), we need to determine the possible integer values of \( x \) that satisfy the condition \( x^2 + y^2 \leq 4 \).

### Step-by-Step Solution:

1. **Understand the Condition**:
The relation states that \( x^2 + y^2 \) must be less than or equal to 4. This describes a circle with a radius of 2 centered at the origin in the coordinate plane.

2. **Determine Possible Values for \( x \)**:
...