Let `A={1,2},\ B={3,6}` and `f: A->B` given by `f(x)=x^2+2\ and\ g: A->B` given by `g(x)=3x` . Verify `f = g` .

Explanation

To verify this we have to show two points

1) domain of (f)=domain of (g) and range of (f)=range of (g)

2) `f(x)=g(x)` for all x in domain

As `f: A->B` and `g: A->B` so first condition is satisfied

Also` f(1)=3=g(1)`

`f(2)=6=g(2)`

thus we can say that` f=g`