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If f: RR->RR be defined as follows: f(x...

If `f: RR->RR` be defined as follows: `f(x)={1,\ if\ x in QQ, -1,\ if\ x !in QQ` Find: `f(1//2),f(pi),\ f(sqrt(2))`

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`f(1//2)=1` as rational
`f(pi)=0` as irrational
`f(sqrt(2))=1`as rational
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RD SHARMA-FUNCTIONS-Solved Examples And Exercises
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