If `f(x) = x^2 - 3x + 4`, then find the values of x satisfying the equation `f(x) = f(2x + 1)`.

Explanation

`f(x)=f(2x+1)`

`=>x^2−3x+4`=`(2x+1)^2-3(2x+1)+4`

`=>x^2-3x+4=(4x^2+4x+1)-(6x+3)+4`

`=>x^2-3x+4=(4x^2-2x+2)`

`=4x^2−2x+2`

`⇒3x^2+x−2=0`

`⇒3x^2+3x−2x−2=0`

`⇒(3x−2)(x+1)=0`

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