If `f(x)=\ {x^2,\ w h e n\ x<0 x ,\ w h e n\ 0lt=x<1 1/x ,\ w h e n\ x >1` Find: i. `f(1//2)` ii. `f(-2)` iii. `f(1)` iv. `f(sqrt(3))` v. `f(-sqrt(3))`

Explanation

Given,`f(x)=x^2`

so

putting various value of x we get


i)`f(1/2)`=1/4

ii )`f(-2)`=4

iii) `f(1)`=1

iv)`f(sqrt(3))`=3

...