If the wave equation `y= 0.08 sin (2 pi)/(lambda) (200t-x)` then the velocity of the wave will be

From a wave equation y= 0.5 sin ((2pi)/3.2)(64t-x). the frequency of the wave is

From a wave equation y= 0.5 sin ((2pi)/3.2)(64t-x). the frequency of the wave is

A transverse wave is represented by the equation y = y_(0) sin (2pi)/(lambda) (vt-x) For what value of lambda is the particle velocity equal to two time the wave velocity ?

A transverse wave is described by the equation y=A sin [2pi(ft-x//lambda)] . The maximum particle velocity is equal the wave velocity if :

Transverse wave is described by the equation y=y_0 sin 2pi (ft-x/lambda) .The maximum particle velocity is twice the wave velocity if wavelength is____

Transverse wave is described by the equation y=y_0 sin 2pi (ft-x/lambda) .The maximum particle velocity is twice the wave velocity if wavelength is____

A simple harmonic wave is represent by the relation y(x,t)=a_(0) sin 2pi(vt-(x)/(lambda)) if the maximum particle velocity is three times the wave velocity, the wavelength lambda of the wave is