If `f(x)=1-1/x` then write the value of `f(f(1/x))dot`

Explanation

Replacing `x` by `frac{1}{x}`

`f(frac{1}{x})=1-frac{1}{frac{1}{x}}=1-x`

Now, `f(f(frac{1}{x}))=1-frac{1}{f(frac{1}{x})}`

`=1-frac{1}{1-x}=frac{1-x-1}{1-x}`

`f(f(frac{1}{x}))=frac{x}{x-1}`