Write the domain and range of function `f(x)` given by `f(x)=1/(sqrt(x-[x]))`

Explanation

`f(x)=frac{1}{sqrt(x-abs(X))}`

`x-abs(x)={(x,-,x,=,0, ifx>=0),(x,+,x,=,2x, if x<0):}`

`x-abs(x)=<=0` for all `x`

`frac{1}{sqrt(x-abs(X))}` does not take any real value for any `x in R`

Hence, domain (`f`)=`phi` and range (`f`)=`phi`