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If f: R->R : x!=0,\ -4lt=xlt=4 and f: A-...

If `f: R->R : x!=0,\ -4lt=xlt=4` and `f: A->A` be defined by `f(x)=(|x|)/x` for `x in A` . Then `A` is `{1,-1}` b. `{x :0lt=xlt=4}` c. `{1}` d. `{x :-4lt=xlt=0}`

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Given that,
`f(x)=|x|/x`
If `x lt 0`
`|x|=x`
...
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